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A particle of mass 1.1454X10^-25 kg. and charge of magnitude 4.8 x 10^-19 C is accelerated from rest in the plane of the page through a potential difference of 218 V between two parallel plates. The particle is injected through a hole in the right-hand plate into a region of space containing a uniform magnetic field of magnitude 0.138 T oriented perpendicular to the plane of the page. The particle curves in a semicircular path and strikes a detector. What is the sign of the charge of the particle? Neglect relativistic effects.
1. The charge cannot be determined for info given.
2. The charge q is negative.
3. The charge q is positive.

2007-02-20 18:28:54 · 3 answers · asked by beehappinow 1 in Science & Mathematics Physics

3 answers

It says the charge has a magnitude of 4.8 x 10^-19 Coloumbs - therefore the charge is positive. The number may be tiny but that it still a +ve charge.

So I would say Answer 3. (seen as though I teach this stuff!!)

2007-02-20 22:47:56 · answer #1 · answered by Doctor Q 6 · 1 1

1, I think you need to know which charge on each plates. May be theres way to figure it out with that magnetic field outside. I'm not sure.

2007-02-20 19:40:04 · answer #2 · answered by Anonymous · 0 0

To hell i hated those things

2007-02-20 18:31:22 · answer #3 · answered by titi 2 · 0 0

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