physics! is any one out there that can show me how to do this?

Question

a racing car accelerates at 12 m/s^2. find the force that the back of the seat exerts on the 95 kg driver.

Answer 1

Remember Newton’s 2nd law,
Force = mass * acceleration

What happens to the driver when the car accelerates at a given rate?
Does the driver fall out of the car or does he stay inside and accelerate too?
Obviously the driver accelerates with the car. The back of the seat pushed on his for some force needed to make his acceleration equal to that of the car.

We are told that the car accelerates at a rate of 12 m/s^2, which also tells us that the driver is accelerating at the same rate.
From Newton’s 2nd law we know that there must be some force applied to the driver which is proportional to the driver’s mass in order to accelerate him at that rate.
We are told that the driver has a mass of 95 kg, so we have all the information we need.

F = ma
F = (95 kg) * (12 m/s^20
F = 1140 Newtons

The seat pushes on the driver with a force of 1140 Newtons.

Answer 2

This problem can be solved using Newton's 2nd law of motion which states:

Force = Mass * Acceleration (F=ma)

In your problem, the acceleration is 12m/s^2 and the mass is 95kg. Using the equation we get:

Force = 12 m/s^2 * 95 kg

So the answer is Force = 1140 Newtons (N)