P + q = 1......P^2 + 2 Pq + q ^2 = 1,.......... questions HELP!!!!?

Question

27% of the population is homozygous dominant for a trait. please tell me how many

- homo. dom.
- hetereo.
- homo rec.
there are

please EXPLAIN YOUR ANSWERS!!!

Answer 1

.27 = p^2 (homozygous dominant)
therefore p=0.5196152422706632
so q = 1-p =.48038475772933675
q^2 = 0.23076951545867358
2pq = 0.4992108959999999

So from this:
P^2 = homozygous dominant = .27
2pq = heterozygous = 0.50
Q^2 = homozygous recessive = 0.23
So this agrees with the equation P^2(.27) + 2Pq(.50) + Q^2 (.23) = 1

If you need to know the frequency of the dominant allele it is the value of P (.52) and the frequency of the recessive allele is the value of q(.48).

Usually in biology decimals are used in place of percents so .27 = 27% and .50 = 50% this is why the equations are written as equal to 1 not 100%

Answer 2

p^2 = 0.27 right off the bat.
Therefore p = 0.519615.
and q = 0.480385

There are 27% homozygous dominant
2pq = 0.499231 = 49.9231% heterozygotes
and q^2 = 0.23077 = 23.077% homozygote recessives.

(With some rounding required)