Yes.
Even if the first seven people were all born on different days of the week, the eighth person would have to be born on the same day as one of the others.
2007-02-20 13:14:56
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answer #1
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answered by Doc Occam 7
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The guy above me left out "Person 1"...
Anyways, yes it's true. Like the 1st guy said... If the 1st seven are born in this order:
1st- Monday
2nd- Tuesday
3rd- Wednesday
4th- Thursday
5th- Friday
6th- Saturday
7th- Sunday
8th- Has to be born on one of the days above
So that means that at least 2 people are born on the same day, yes.
2007-02-20 21:24:15
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answer #2
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answered by TheBosnian 2
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Of course not. Plan it out.
Person 2, born any day: 7:7
Person 3, limited: 6:7
Person 4, more limited: 5:7
Person 5, more limited: 4:7
Person 6, more limited: 3:7
Person 7, more limited: 2:7
Person 8, only 1:7.
You are dealing with statistical probability, and in that subject, the first thing you learn is that there is NO such thing as a "sure thing." Else, how would casinos stay in business?
2007-02-20 21:18:46
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answer #3
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answered by Anonymous
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Would it make a difference if it were a leap year? I'm not sure I was just curious.
2007-02-20 21:36:07
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answer #4
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answered by kelbel 1
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