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The resistance distance is 4 meters and the resistance weighs 80 Newtons. The effort distace is 12 meters. How much effort force must be applied to lift the resistance?

2007-02-20 12:45:13 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Dr*Fr = De * Fe
4(80) = 12 (Fe)

And solve for Effort Force. (Advanced?)

2007-02-20 12:51:47 · answer #1 · answered by Dennis H 4 · 1 0

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