The sun would be at your back (sort of) so the Earth would be full... at least until the moon's shadow crossed it. The Earth would appear larger than the moon does from Earth, so the shadow wouldn't completely cover the Earth the way the Earth's shadow covers the moon.
2007-02-20 13:07:17
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answer #1
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answered by eggman 7
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The sun would be at your feet and would shine on the whole side of the earth facing the moon. You would be able to see a shadow of the moon on the earth. Click on the following link to see a picture of the moon's shadow during an eclipse of the sun by the moon: http://antwrp.gsfc.nasa.gov/apod/ap040926.html
2007-02-20 13:39:48
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answer #2
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answered by Twizard113 5
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If the moon were stopped at its modern-day altitude it would certainly fall onto earth. notwithstanding the moon has slightly of speed it really is at proper angles to the line between it and the earth, and the gravitational rigidity between moon and earth keeps this element at proper angles by forcing it into an elliptical yet close to-round route. This consistent inward acceleration does no longer advise the area is replacing, it really is in simple terms what takes position whenever you rigidity an merchandise to commute in a rounded route truly than the immediately line it would commute in if no rigidity were appearing on it. it really is the position the pail-on-a-string analogy comes from. The gravitational rigidity acts because the string. So is this a precariously balanced scenario? What takes position if an merchandise in orbit slows down some? the answer isn't a lot. sluggish it a touch and it starts dropping altitude, yet jointly it features speed; the entire power remains an similar because it became at modern-day after slowing. The benefit in speed is correct at the same time as the article is at its lowest factor, and this power then facilitates it to attain altitude on the cost of %. Slowing it down a touch in simple terms places the article in yet another good orbit of a lot less power than the unique one. So typically an orbit is a self-conserving subject, until eventually the altitude loss is so tremendous that the article enters the ambience and slows extra by using tug, or collides with the earth's floor. That sluggish outward waft said in between the solutions is almost touching on to this theory (yet no longer sufficient for an in intensity rationalization the following). The moon-earth gravitational rigidity motives tides and distortion of the coolest bodies, which use up power as friction and warm temperature. This leads to a "coupling" of rotation between earth and moon, and the moon features a touch angular momentum from the earth, and the earth's rotation slows particularly for this reason.
2016-12-04 10:50:28
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answer #3
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answered by endicott 4
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Yes, full phase. The moon is directly between the Earth and the sun.
2007-02-20 13:06:04
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answer #4
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answered by nick s 6
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The Earth would be full. You might be able to make out the moon's shadow as it fell on the Earth.
2007-02-20 12:51:33
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answer #5
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answered by Pseudo Obscure 6
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the shadow of the moon would not be large enough to cover the entire earth. so you would not see anything like the phases of the moon.
what you would see, is a dot of complete shadow, surrounded by a larger dot of semi-shadow moving over the surface of the earth. these dots would resemble the form of a flashlights torchspot, but in exact opposit. (light being shadow)
2007-02-20 13:13:27
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answer #6
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answered by mrzwink 7
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Full phase since you'd be seeing the side of the earth facing the sun.
2007-02-20 12:51:42
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answer #7
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answered by Roman Soldier 5
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A new earth (like a new moon).
2007-02-20 12:48:19
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answer #8
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answered by Anonymous
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I don't know the phase name but it would be in complete shadow.
2007-02-20 12:47:36
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answer #9
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answered by Anonymous
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