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The sides of a cone make an angle "THETA" with the vertical. A small mass "m" is placed on the inside of the cone and the cone, with its point down, is revolved at a frequency "f" about its symmetry axis. If the coefficient of static friction is "MU", at what positions on the cone can the mass be placed without sliding on the code? (Give the maximum and minimum distances, "r", from the axis)


I guess what it boils down to is what forces are acting on the mass... what am I missing. So far I have these forces:
Centripetal, friction, and gravity. Is that it? And is (f/(2*pi*r)) equal to velocity?

2007-02-20 12:10:26 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

v=2 pi f r and F=mv^2 / r
find normal force perpendicular to surface of cone as a function of r by finding the components of the gravitational and centripetal force normal to the surface. Then calculate the frictional force and set it equal to the components of the gravitational and centripetal force parallel to the surface. Solve for r, you should get 2 values.

2007-02-20 16:02:00 · answer #1 · answered by meg 7 · 0 0

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2016-09-29 09:45:12 · answer #2 · answered by barksdale 4 · 0 0

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