A ball dropped to the floor rises to a height less than its original height. Discuss the energy conversion.?

Question

Here is what I have so far, please let me know if I'm on the right track. Thanks!

When the ball hits the floor each successive time, some of the energy gets transferred to the floor as impact and heat energy. Further, some of the energy is expended in moving against air friction. Therefore, each successive time, the ball rises to a lower height because of energy losses.

As the ball falls, gravitational potential energy is converted into kinetic energy. When the ball hits the floor, some of the kinetic energy is converted to sound energy and heat, some to a compression of the ball-like compressing a spring. The ball now rebounds, converting the potential energy of compression back to kinetic energy. Finally, the kinetic energy of the ball is converted back to potential gravitational energy as the ball rises. The final height of the ball is less than its initial height because some energy has left the system in the form of sound and heat.

Answer 1

This sounds about right to me (apart from "impact" energy - which I don't think exists). I think that you should also consider the heat generated when the ball rebounds as well as the kinetic energy against gravity. The elastic deformation of the ball as it is compressed will generate some heat.
If you want to be a stickler, no energy leaves the system - it is just converted into another form - transfered from the the ball to the rest of the system as its entropy increases. The total number of joules in the system (i.e. in the Universe) remains the same.