Calculate the peak current in a 8.6 k resistor connected to a 120 V rms ac source.?

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Calculate the peak current in a 8.6 k resistor connected to a 120 V rms ac source.?

2007-02-20 08:45:29 · 2 answers · asked by Minamoto 1 in Science & Mathematics ➔ Physics

2 answers

Multiply 120 times 1.41 to get peak voltage. Current now equals that peak voltage divided by 8.6K ohms.

I = E(peak)/R

I'll let you do the math.

2007-02-20 08:52:07 · answer #1 · answered by Joseph F 5 · 0⤊ 0⤋

assume the resistor is the sole reactance interior the circuit -- source resistance is negligible. Calculate the top voltage: If the source is purely sinusoidal, the top is one million.414 * RMS. one million.414 * a hundred and twenty V. Use Ohm's regulation E = IR or I = E/R = one million.414 *a hundred and twenty / 7.8k amps Get out your calculator, i'm shifting on.

2016-10-16 03:01:22 · answer #2 · answered by balikos 4 · 0⤊ 0⤋