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There are three symbols in relativity textbooks that I've never encoutered before and need lots of help with.

1.Einstein summation convetion : Though not really a symbol i still don't quite understand what is meant by it.

2. Upper case lambda with super scripts and subscripts: It seems to be some sort of linear transformation, but I still don't quite understand it.

3. The great demon, the kronecker delta: I really cannot understand what is meant by this.

The reason I have such a hard time with this notation is because I have very little formal education.

However after the symbols are understood, it becomes very lucid.

Can someone please give me a CLEAR and informal description of what this means with examples relating to relativity and tensor analysis?

PS. I don't want some freaking link to wikipedia! Those have no useful information and seem to me like an attempt at increasing the number of questions you answer.

2007-02-20 08:34:15 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

I confess all (or most) of what I know about this, I learned from Wikipedia. Here's my attempt (and ^ means superscript, and not necessarily exponentiation):

1. The number i here is not defined as anything, so it is a counter, where f(x^i) = Sum(x_i) where i starts at 1 (or 0 in some texts, where a start of 1 is used for Greek letters), and goes to n, or whatever the predefined upper limit.[1]

Now, to represent vectors, the same idea is used, except this time, we are demonstrating what the index of the vector is, rather than adding them up. Thus, u^i = (u_1, u_2, ..., u_n) = [u_1 u_2 ... u_n]^T (a column vector). And v_j = [v_1 v_2 ... v_n] (a row vector).[2]

You get the idea. Basically it means repeat for each applicable i, and (in your case) add the results.

2. I was unable to find anything on Λ, except for something on astronomy, which I doubt would be what you were looking for. Perhaps you want Einstein notation for using the Von Mangoldt function?

3. You might think of delta_ij as being the value of the jth entry in the ith row of any sufficiently large identity matrix, since it has 1s down the diagonal, and 0s elsewhere.

A formal definition is delta_ij = 1 (if i = j) or 0 (if i != j), or using the Iverson bracket, delta_ij = [i = j].[3]

Thus, delta_46 = 0, but delta_77 = 1.

~~~
Sorry about #2. I guess 2/3 isn't bad!

2007-02-23 11:33:29 · answer #1 · answered by Anonymous · 0 0

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2016-09-29 09:31:47 · answer #2 · answered by gizzi 4 · 0 0

http://www.amazon.com/gp/reader/0070334846/ref=sib_dp_pt/104-2479740-8363901#reader-link
You can see the first chapter of this book on line. It will answer many of your questions. You need to get a book on tensors and learn a little math to understand relativity.

2007-02-20 12:31:14 · answer #3 · answered by meg 7 · 0 0

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