What is the average deceleration force on the mass?

Question

If a 10kg mass is dropped from a height of 2 meters (free fall for this distance) and then rapidly decelerates to a stop in just 1cm distance. What is the average deceleration force on the mass?

Answer 1

The mass is dropping by free fall through 199 cm. Its velocity by then would be v^2 - 0 = 2 g.199 in cm (g also should be used in cm/sec^2)

Now this v is to be brought to 0 in 1 cm. So, we have,

0 - v^2 = - 2.d.1 (let d be the decelerating force)

d = v^2 / 2 = 2.g.199 / 2 = g.199 cm/sec^2

d is 199 times greater than g.

Answer 2

Depends on the impendance,impedance.