x2 – 6x + 8/(x2 – 4)
simpify
2007-02-20 02:00:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Factorize the top and bottom to become:
(x-2)(x-4) / (x+2)(x-2)
Cancel down
(x-4) / (x+2)
You can check by substitution
2007-02-20 02:05:59 · answer #1 · answered by Kristina P 2 · 0⤊ 0⤋
Simplify (x^2-6x+8)/(x^2-4)
First: factor the numerator > multiply the 1st & 3rd coefficient to get "8." Find two numbers that give you "8" when multiplied & "-6" (2nd/middle coefficient) when added/subtracted. The numbers are (- 4 & - 2).
*Rewrite the numerator with the new middle coefficients.
x^2 - 4x - 2x + 8
*With 4 terms - group "like" terms & factor both sets of parenthesis.
(x^2 - 4x) - (2x + 8)
x(x - 4) - 2(x - 4)
(x - 4)(x - 2)
Now, you have....
[(x - 4)(x - 2)/(x^2 - 4)]
Sec: factor the denominator - its the Difference of Squares.
[(x - 4)(x - 2)/(x + 2)(x - 2)]
Third: cross cancel "like" terms.
(x - 4)/(x + 2)
2007-02-20 10:49:05 · answer #2 · answered by ♪♥Annie♥♪ 6 · 1⤊ 1⤋
x² - 6x + 8 / x² - 4 =
(x - 4)(x - 2) / (x - 2)(x + 2) =
(x - 4) / x + 2
- - - - - - - - - - - -s-
2007-02-20 11:10:07 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
factorize it then after multiplication divide the product with the answer.
2007-02-20 10:09:07 · answer #4 · answered by aaayush 2 · 0⤊ 0⤋