please help.?

Question

just in case people think i'm trying to get homework answer, i'm totally not. algebra is my worst subject, so if my answers are way off please don't laugh.

Find the x-intercept of the graph of the equation: x+6y=7
my answer: 1
Find the y-intercept of the graph of the equation: y-3x=4
my answer: -7
Find the slope of the of the graph of the equation: y=5-3x
my answer: 3
Fnd the slope of the line passing through the points: (2,4) and (1,3)
my answer: -1/1
Write an equation of the line in slope intercept form given the slope is -5 and the y-intercept is 7
my answer: y=-5x+7

Answer 1

I'm going to label the questions a, b, c, etc...

a) x-intercept is where the graph crosses the x axis, meaning y=0, so substitute y=0 into x+6y=7
x + 6(0) = 7
x = 7

b) y-intercept is where the graph crosses the y axis, meanign x=0, so substitute x=0 into y-3x=4
y-3(0) =4
y = 4

c) slope of graph... the generic equation for a line is: y = mx +b. b is the y intercept (for future use), the slope is m.
so rearranging your original equation:
y = -3x +5
m = -3 and that is your slope

d) slope is equal to delta Y divided by delta X or change in y divided by change in x
m = (4-3)/(2-1) = 1/1 = 1

e) again, generic equation for a line is y = mx +b
so with the information you have:
y = -5x +7 (WELL DONE!)

Hope it helps...