dis is phy problem?

Question

a gun is fired from top of the hill 100mm above sea level 10 sec later.the bullet found to hit the warship1km away from gun position.determine the velocity and the angle of projection of bullet .with wat velocity the bullet strikes the warship

Answer 1

h=1/2 g t^2=100
t^2=20 sec
t2=10sec
s=1/2gt^2+vt cosX=1000=0.5 10 100+v 10 cosX
1000-500=v 10 cosX
500=10 vcosX
50=v cosX ,,,,v=gt=10 10 =100m/sec
50=100cosX,,,,cosX=0.5 X=60^^

Answer 2

You can't call that a hill.