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I know how to use the formula for osmotic pressure, however the way that this problem incorporates partial pressure into it just confuses the sh*t outta me. Please help me, before I cut my wrists.


The partial pressure of O2 in air at sea level is 0.21 atm. The solubility of O2 in water is 1.38 x 10-3 M at 20°C and Poxygen = 1.00 atm. Calculate the molar concentration of O2 in the surface water of a mountain lake saturated with air at 20°C and an atmospheric pressure of 662.8 torr.

2007-02-19 21:42:24 · 2 answers · asked by AppleCard! 2 in Science & Mathematics Chemistry

2 answers

You need no osmotic pressure but henry law

c=kp here the number of mole of O2 dissolved is c p is the pressure k is expreesed for a voume of 1L

so here c =1.38 10^-3 * 0.21 * 662.8/760= 2.53 10^-4mole/L

I explain 1.38 10^-3 is for 1 atm =760 torrs so here you have only 662.8 torr hence the ratio 662.8/760 and the number 0.21 since O2 IS ONLY 0.21

2007-02-19 22:48:36 · answer #1 · answered by maussy 7 · 0 0

8.55 = CRT = C x 0.08206 x 280 C = 0.372 = moles sucrose / 0.548 moles sucrose = 0.204 multiply by the molar mass

2016-05-23 22:10:13 · answer #2 · answered by Anonymous · 0 0

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