x^-1(x^-2+x^-3) = ?

Question

read as, x to the power of neg one (x to the power of neg 2 plus x to the power of neg 3) = ? help pls! =)

Answer 1

x^-3 + x^-4

Answer 2

(1/x)(1/x^2 + 1/x^3) =
(1/x^3 + 1/x^4) =
(x + 1)/x^4

Answer 3

x^-1(x^-2 + x^-3) =
1/(x^(1/x^2 + 1/x^3) =
1/(x^((x+1)/x^3) =
x^(x^3/(x+1))

Answer 4

Simplify: x^-1(x^-2 + x^-3)

First: eliminate parenthesis --- distribute the outer term with the terms in parenthesis.

(x^-1)(x^-2) + (x^-1)(x^-3)

Sec: when you multiply the same variable --- add exponents.

x^-1+(-2) + x^-1+(-3)

x^(-1-2) + x^(-1-3)

x^-3 + x^-4

Third: rule - variables have positive exponents. Change the variables into fractions - place the variables over 1.

(x^-3)/1 + (x^-4)/1

*Place the x-variables in the denominators.

1/x^3 + 1/x^4 Or, (x+1)/x^4

Answer 5

x^-1(x^-2+x^-3)
=x^-3+x^-4
=1/x^3+1/x^4
=(x+1)/x^4

Answer 6

x^-1(x^-2 + X^-3) =
x^-3 + x^-4 = (when you multiply simply add exponents)

1/x^3 + 1/x^4 that about all that can be done with th given info

Answer 7

hi im in algebra suitable now too. so your issue is x^2+6x+9. nicely you already know you % an x in each and every set of (). so it could appear like (x ) (x ). now the two sign are the comparable AND postive so your issue could be (x+ ) (x+ ). now the climate of 9 are 1x9 and 3x3. Now which words while extra supply you with 6. ( 3 and 3 needless to say!) so as that could supply you with (x+3)(x+3). use the FOIL technique to benefit. sturdy luck ^^!

Answer 8

1/x (1/x^2 +1/x^3 ) =
1/x^3 +1/x^4 =
x^-3 + x^-4
or
= (x+1)/x^4