one angle of a triangle measures twice the smallesangle. The third angle is six times the measure of the small

Answer 1

How about 20 - 40 - and 120 degrees............

Answer 2

The way you solve this problem is by creating some equations. Angle A will be the smallest Angle B will be another angle Angle C will the last angle Since an triangle has 3 angles and a total of 180 degrees, we know that A+B+C=180 Angle B is 20 degrees more than the smallest angle A. So B=A+20 Angle C is 2 times the size of A. So C=2A Now we will take what B and C equal and place them in the original equation A+A+20+2A=180 This simplifies to: 4A+20=180 Subtract 20 from each side 4A=160 divide each side by 4 A=40 Now that we know that A, the smallest angle is 40 degrees, we take A and put it into the equations we got for B and C. B=A+20 B=40+20 B=60 C=2A C=2*40 C=80 Angle A is 40 degrees Angle B is 60 degrees Angle C is 80 degrees

Answer 3

I don't know how to do degrees on my computer, but the angles (from smallest to largest) measure: 20 degrees 40 degrees and 120 degrees.

smallest angle = x
x+2x+6x= 180 because there are 180 degrees in every triangle
9x=180 combine like terms
x=20 divide
x = 20 smallest angle
2x = 40 middle angle
6x = 120 largest angle

Answer 4

1 angle equal to 20(small angle) and twice that is 40(second angle) and 20(small angle) times 6 equals to 120 and add all the angles and it equals to 180 and any triangle equals 180

Answer 5

1x +2x+6x = 180
9x = 180
x = 20
2x = 40
6x = 120
20 is the smallest. 2 times that smallest is 40 and 6 times the smallest is 120. Together it is 180.

Answer 6

And the sum of all the angle is 180º, so add up all the angles and solve for the smallest angle

Answer 7

Well think about it... 180 degrees is a triangle...
let's do some algebra
180=x+2x+7x
180=10x
18=x
x=smallest angle.. and you can do the rest

Answer 8

20 degrees
40 degrees
120 degrees

Answer 9

a+b+c=180
a=2b
c=6b

2b+b+6b=180 9b=180 b=20
a=2b=40
c=6b=120