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The bottom is 8, and the 2 sides are 5.

2007-02-19 16:12:21 · 7 answers · asked by Emo B 5 in Science & Mathematics Mathematics

7 answers

divide the triangle into 2, down the center so you have a base of 4, and a "side" (hypotenuse) of 5. use pythagorus....height = square root of ((5^2)-(4^2)). done. (answer is 3, but try to get it yourself so you know why)

2007-02-19 16:18:16 · answer #1 · answered by aaron p 2 · 0 0

it's an isoceles triangle so draw out the triangle and label the sides. then split the triangle directly down the center. Now you have two triangles, sharing a similar side. That similar side is the height of the triangle and the length of it is what you need to find. Since the height forms a 90 degree angle with the base, you can use the pythagorean theorem to find the length. since you cut the triangle in half, the base length is now 4.

a^2 + b^2 = c^2
4^2 + b^2 = 5^2
b^2 = 25 - 16
b = 3

2007-02-20 00:19:54 · answer #2 · answered by tim 1 · 0 0

The altitude or height is the perpendicular distance from the vertex to the base. Since this is an isosceles triangle, the altitude divides the base into two equal segments of 4 units each.

So you have a right triangle with hypotenuse = 5 and on leg = 4.

By the Pythgorean Theorem, the other leg (the height)must be sqrt(5^2-4^) = sqrt(25-16) = sqrt(9) = 3

2007-02-20 00:23:37 · answer #3 · answered by ironduke8159 7 · 0 0

This is an isosceles triangle. If you drop a perpendicular from the vertex to the base (bottom) you will form two congruent right triangles with
hypotenuse = 5
one leg = 4
height (other leg) = h

By the Pythagorean Theorem

h² = 5² - 4² = 25 - 16 = 9
h = 3

The height of the triangle is 3.

2007-02-20 00:36:48 · answer #4 · answered by Northstar 7 · 0 0

The height is 3.

Because two sides are of length 5, this is an equilateral triangle, so the point where the two equal sides meet (the "vertex") is DIRECTLY above the midpoint of the length 8, making a right-angle there. Draw in the line from the vertex to that midpoint. Each of the two triangles now stuck together (having the perpendicular "height" in common), are right-angled triangles with hypoteneuse 5, and another side (half the base of your original triangle) of length 4.

The most famous and basic "Pythogorean triple" for right-angled triangles is (3, 4, 5), and YOU now have TWO of them, with what is called the "height" of your triangle of length 3.

QED.

Live long and prosper.

2007-02-20 00:16:34 · answer #5 · answered by Dr Spock 6 · 0 0

If the two sides are 5,it means it is anisoceles triangle.Hence the altitude or height will bisect the base at mid point.
If ABC is the triangle and AD is the height.Then ABD is a right angled triangle and AD^2=AB^-BD^2
=5^2-4^2
=25-16=3^2 Therefore AD=3

2007-02-20 00:22:11 · answer #6 · answered by alpha 7 · 0 1

its a special right triangles

so 5 , 4, 3

2007-02-20 00:18:24 · answer #7 · answered by I LOVE YANKS & DESPISE REDNECKS 1 · 0 1

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