Pre- Calc Help!?

Question

I'm doing my pre- calc. I need help. I don't remember how to find the LCD, of equations like this (x-6)/(x^2-2) I just can't seem to find the LCD. I also have equations such as 1/m=(m-34)/2m^2.. You must solve this one. Can anyone help me?

Answer 1

I am not sure about a couple of things. To find the lowest common denominator, you must have two fractions. Then from those fractions, you can find the LCD. You just gave one.

1/m = (m-34)/m^2

All you have to do is multiply both sides by m^2

m = .(m-34)/2
m = 0.5m - 17
0.5m = -17

m = -34

How do you check this answer? Simple, plug it back into the original equation and see if it works out.

Answer 2

I'm assumming that you're solving for m in this equation

first>> 1/m = (m - 34)/(2 * m^2)
>> 2m = m - 34 (Multiply both sides by 2m^2)
>> m = -34 (Subtract m from both sides)

If I read your question correctly, this is the ans.

Hope it helps

Answer 3

Don't freak out girl, this is algebra stuff. You've dont it all before. For the first one, x^2-2 unfoil it, it's a perfect sq. (x-1) (x+1) when you divide, you flip the second part of the equation (reciprical) When you add and subtract, make sure to make it common denomenators first, and make sure you can move things to the same side, sometimes with inequalities, it's better to wait. Breath, look at your examples, everything will be alright, just wait till you get to trigonometric identities with Cos, Sin, and Tan. and need to Prove and solve them. ^_- this is easy peasy stuff. Quake in your boots when you get to the radian unit cirle trig.