A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 20.6 ° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 52.3 kg, and the coefficient of kinetic friction between the skis and the snow is 0.183. Find the magnitude of the force that the tow bar exerts on the skier.
2007-02-19 13:31:33 · 2 answers · asked by sweetbolbola 2 in Science & Mathematics ➔ Physics
is mg 52.3?
2007-02-19 13:47:41 · update #1
Constant velocity means a = 0, so force down plane = force up plane.
F = mgsintheta + mumgcostheta
mu =.183
substitute and solve
2007-02-19 13:39:58 · answer #1 · answered by hello 6 · 0⤊ 0⤋
First draw a force diagram.
A=angle of slope
On the diagram you should lable the force F pulling the skier, the weight mg, the normal N to the skier, the resolved force of the skiers weight down-hill and the force of kinectic friction Nk. You'll see from the diagram that the force to full the skier is equal to N
mgsin(A)+kmgcos(A)
plugging values we get
9.8*52.3sin(20.6)+.183*9.8*52.3cos(20.6)
2007-02-19 21:46:00 · answer #2 · answered by Rob M 4 · 0⤊ 0⤋