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the power supply of a battery that is

2007-02-19 12:05:37 · 1 answers · asked by Logan 4 in Science & Mathematics Physics

1 answers

There is a time dependency.

I assume that the capcitor and resistor are in series with the battery. If there is also a switch in the circuit, then at time equal zero, there is only voltage across the battery.

When the switch is thrown there is a time depenency of the voltage on the capacitor:

v(t)=v(supply)*(1-1/e^(t/T))

where T is the time constant of the circuit
T=R*C

the resistor on the other hand, will have voltage equal to
v(t)=v(supply)*(1/e^(t/T))

when t>>T, the resistor will have no voltage and the capacitor will have voltage equal to supply

j

2007-02-19 12:31:52 · answer #1 · answered by odu83 7 · 0 0

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