derivative of f when f(x)= 2x sinx- x^2cosx?

Question

A) f'(x)= -(x^2+2) sinx
B) f'(x)= -(x^2+2) cosx
C) f'(x)= (x^2 -2) cosx
D) f'(x)= (x^2+2) sinx
E) f'(x)= -(x^2-2) sinx
F) f'(x)= (x^2+2) cos x

Answer 1

Use product rule
2xcosx + 2sinx - (2xcosx + x^2sinx)

combine to get

(2-x^2)sinx

or

-(x^-2)sinx

E

Answer 2

product rule:
2sinx+2xcosx-2xcosx-x^2sinx
(2-x^2)sinx
-(x^2-2)sinx
E

Answer 3

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