They need to be factored to look similar to this model: (x - 3)(x+4)
5x^2 + 31x - 28
4x^3y - 20 x^2y + 16 xy
x^2 - 18 + 81
5x^3 - 50x^2 + 45
-x^4 + 2x^2 + 8
125x^2y - 5x^4
Answer as many as you can. I'll take all the help I can get!
2007-02-19 11:28:33 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
1. (x+7)(5x-4)
2. 4xy(x-4)(x-1)
3. (x-9)(x-9) or (x-9)^2
4. 5(x-9)(x^2-1) or 5(x-9)(x+1)(x-1)
5. -1(x+2)(x-2)(x^2+2)
Hope this helps
2007-02-19 11:46:29 · answer #1 · answered by Barbara H 5 · 0⤊ 0⤋
Factor the variables and numbers separately for each polynomial. Remember that an "x^2" means it has two Xs. Numbers like 5 that are prime numbers (divisible only by themselves and 1) cannot be factored any further, so use a one in the other set of parentheses. Numbers like 81 are squares and can be factored into 9 and 9. Numbers like 20 that are not primes or squares can still be factored, such as 10 and 2 for 20. Start each problem by looking at the last term (the one with no Xs or Ys in it) and thinking of what could combine to make that number.
2007-02-19 12:03:03 · answer #2 · answered by Barry D 2 · 0⤊ 0⤋
Graph them on your scientific calculation and look for 0
2007-02-19 11:42:19 · answer #3 · answered by Raul R 1 · 0⤊ 0⤋
go to webmath.com
they have a solver that will do stuff like this for you.
2007-02-19 12:19:59 · answer #4 · answered by billy 1 · 0⤊ 0⤋