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"Consider a mass m hanging vertically from the end of a spring of force constant k. In equilibrium, the mass rests at a position y = y0 = mg/k. Starting from Newton’s second law, show that if the mass is displaced from equilibrium a distance A and then released, it will follow simple harmonic motion about the position y0." Good luck!

2007-02-19 10:46:12 · 1 answers · asked by Goose 2 in Science & Mathematics Physics

1 answers

Just write the differential equation and solve it, and you'll see that it follows simple harmonic motion.

2007-02-19 10:53:58 · answer #1 · answered by actuator 5 · 0 1

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