Coasting along at 7.10 m/s, a 60.0 kg bicyclist on a 7.60 kg bicycle encounters a small hill.?

Question

Coasting along at 7.10 m/s, a 60.0 kg bicyclist on a 7.60 kg bicycle encounters a small hill. If the speed of the bicyclist is 6.00 m/s at the top of the hill, how much work was done on the bicyclist and her bike?

Can anyone show me how to do this? Thanks.

I tried the answer below and it was wrong. I re-did the problem and got the same answer. I don't think the conservation of Energy works here. He is going up a hill so that means hed gain potential energy and natuarally lost Kinetic Energy. So we really don't know the amount of Energy lost to work done. maybe the conservation of momentem would work?

Answer 1

since the bicycle is coasting, look at the difference in kinetic energy to compute the work done:

.5*m*(v1^2-v2^2)
=.5*67.60*(7.10^2-6^2)
=487 J

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