Two packing crates of masses m1 = 10.0 kg and m2 = 6.50 kg are connected by a light string that passes over a frictionless pulley as in Figure P4.26. The 6.50 kg crate lies on a smooth incline of angle 35.0°. Find the acceleration of the 6.50 kg crate.
2007-02-19 08:02:19 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
FIGURE: http://s104.photobucket.com/albums/m200/patriciaisaac/?action=view¤t=image.jpg
2007-02-19 08:34:29 · update #1
Equate the 2 accelerations: a1 = a2 = (m1g-T)/m1 = (T-m2gsin35)/m2
This will give you a value for T which can be plugged into either of the formulas to give the acceleration.
I got T = 60.75 N & a = 3.725 m/s²
2007-02-19 09:34:02 · answer #1 · answered by Steve 7 · 1⤊ 0⤋
first of all, since the two masses are connected to each other, you must assume that they have equal accelerations. So, the mass of m1 would be 3.50 kg. Using this and gravity as G =- 9.81 m/s^2, you can assume that it is falling down with an acceleration of 9.81 m/s^2. Then, because the string connect the two masses, the acceleration of m2 is also 9.81 m/s^2, but in the upward direction.
2007-02-19 17:02:55 · answer #2 · answered by kyle2920 2 · 0⤊ 0⤋
Can you link Figure P4.26?
2007-02-19 16:29:00 · answer #3 · answered by STEVEN F 7 · 0⤊ 0⤋