Need Help Solving this equation 6-(x-2)=3(x+1)?

Question

Can anyone help me solve it step by step?

Answer 1

6 - ( X - 2 ) = 3( X + 1)

Step 1. Simplify the left side of the equation. Work the bracket and distribute the minus sign to X and -2.

- ( X - 2 ) = - (+) X - (-) 2 = -X + 2 notice the minus become a plus minus sign * minus sign = plus sign

6 - X +2 = 3 ( X + 1 )

- X + 8 = 3 ( X + 1 )

Step 2. Simplify the right side of the equation. Work the bracket and distribute the value 3 into X and 1 by multiplication.

3 ( X + 1 ) = (3)*X + (3)*1 = 3X + 3

-X + 8 = 3X + 3

Step 3. Simplify: Get all the Xs in 1 side of the equation and the value at the other

-X + 8 = 3X + 3

-X + 8 + X = 3X + 3 + X ------> add X to both sides to get rid of -X on the left side of the equation

8 = 4X + 3

8 - 3 = 4X + 3 - 3 ------- Now ADD (-3) to both sides to get rid of the (+3) on the right hand of the equation.

5 = 4X
Answer: X = 5/4

Answer 2

Strip the parentheses by doing the indicated multiplication to get:
6 - x + 2 = 3x + 3.
Collect terms:
5 = 4x
Simplify:
x = 5/4.

Answer 3

6 - (X-2) = 3(x+1)

lets start with 3(x+1) multiply 3 through the parenthesis

so you get 3x+3

now for 6 -(x-2) since your subtracting (x-2) from 6 you can put the negative symbol through so you have

6-x+2 (since your subtracting a -2 it turns it positive)

so you have x+8 = 4x+3 so move the x's to one side

5 = 4x x= 5/4 or 1.25

Answer 4

6-(x-2)=3(x+1)
6-x+2=3x+3, use distributive property
8-x=3x+3, combine like terms (6 and 2 on left side)
8=4x+3, move variables to one side of =
5=4x, -3 on both sides
5/4 (or 1.25)=x, divide by 4 (in front of x)

Answer 5

6-(x-2)=3(x+1)
6-x+2=3x+3
8-x=3x+3
8-3=3x+1x
5=4x
x=5/4= 1-1/4