solve by factoring 25y^2-52y+27?

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2007-02-19 04:46:15 · 4 answers · asked by ashlovthebeach 1 in Science & Mathematics ➔ Mathematics

(25y - 27) (y - 1 )

2007-02-19 04:50:05 · answer #1 · answered by John T 6 · 0⤊ 0⤋

25y^2-52y+27
(25y-27)(y-1)
25y-27=0
25y=27
y=27/25=1.08

y-1=0
y=1

y=1, 1.08

2007-02-19 12:53:39 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋

(25y - 27)(y - 1)

2007-02-19 12:51:39 · answer #3 · answered by True_D 1 · 0⤊ 0⤋

(25x -27)(x-1)=0
25x-27=0 or x-1 = 0
x = 27/25 or x =1

2007-02-19 12:53:01 · answer #4 · answered by leo 6 · 0⤊ 0⤋