How does the force of gravity between two object change when the distance between them is tripled?
ANOTHER QUESTION ABOUT Impulse
If a tennis ball and a bowling ball collide in midair does each undergo the same amount of impulse? explain you answer.
2007-02-19 04:42:18 · 3 answers · asked by Johnnyboy 2 in Science & Mathematics ➔ Physics
As for part one, the masses involved are so slight that they would be unmeasurable. However, if both were dropped at the same time, they would both fall at the same rate.
Part two, the tennis ball will rebound with a greater force due it it's much lower mass and the bowling ball will so little if any effects from the collision.
2007-02-19 04:51:19 · answer #1 · answered by Hecaeta 3 · 0⤊ 0⤋
F = GmM / d^2
Force = G(constant) Mass1 Mass2 / distance Squared
F = GmM / (3d)^2
F = GmM / 9 d^2
So gravity at triple distance is 1/9 what it was.
Impulse see link
2007-02-19 12:49:36 · answer #2 · answered by Grant d 4 · 0⤊ 0⤋
M1 = mass of object 1
M2 = mass of object 2
G = Newton's constant of gravitation
D = distance between objects.
F = (G*M1*M2) / (D^2)
Therefore if the distance is tripled, the gravitational attraction will be one-ninth as strong. (inverse square law)
2007-02-19 12:48:30 · answer #3 · answered by John T 6 · 0⤊ 0⤋