the chance of flipping a coin and getting a heads is 50%. The chance of spinning a spinner and getting red is 20%. What is the probability of spinning a spinner and getting red, and then flipping a coin and getting a heads?
and another one: There are 10 lollipops in a jar. 7 of them are cherry and 3 are lemon. If Mike and Mary both take one lollipop, what is the probability they will both get cherry?
2007-02-19 04:15:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
these questions are easy. are you trying to solve your homework.
if these are truley your problems. you are welcome
answer1: probability is 0.01 OR 10 %
answer 2: 7C2/10C2 =7/15=.47
OR 46.67%
2007-02-19 04:31:32 · answer #1 · answered by Anonymous · 1⤊ 0⤋
1. probability of heads is 50%, probability of red is 20%, so
0.50 * 0.20 = 10%
2. probability of Mike is 7/10, then Mary is 6/9 because one lollipop is gone
.7 * .67 = 36.9%
2007-02-19 12:30:14 · answer #2 · answered by leo 6 · 0⤊ 0⤋
2 is wrong. Once the first cherry is removed, the p(cherry) becomes 6/9
2007-02-19 12:24:35 · answer #3 · answered by modulo_function 7 · 1⤊ 0⤋
1) 10% (1/2 x 1/5)
2) 49% (7/10 x 7/10)
2007-02-19 12:22:41 · answer #4 · answered by Jenae73 3 · 0⤊ 1⤋
you need to draw tree diagrams to answer both of these questions. multiply the fractions along the branches to find your answers.
2007-02-19 12:32:59 · answer #5 · answered by Anonymous · 0⤊ 0⤋