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such as we can write o\o as
(2)(2)-(2)(2)\2-2 or (2-2)(2+2)\(2-2) and if 2-2 is cancelled by 2-2 then we get the answer 2+2=4.we can put different values to get different answers.so tell me the the exact value.

2007-02-19 04:01:30 · 17 answers · asked by Anonymous in Science & Mathematics Mathematics

17 answers

0/0 is indetermine.

Your example has some problem because you cannot cancel
2-2 like that since denominator is 0.
So, (2-2)(2+2)/(2-2) is not allowed to cancel by 2-2.

To find 0/0, we try one example
let say x = 0/0
x (0) = 0
x can be any number, thus indetermine
So, 0/0 is indetermine!!!

2007-02-19 04:21:39 · answer #1 · answered by seah 7 · 2 0

As you said, you can get different answers if you use different numbers, and that's an important part of *why* 0/0 is undefined.

One way to define division is through multiplication: we say that a division problem a/b has the answer c (that is, a/b=c) if a=bc (the corresponding multiplication problem). But this completely breaks down if b=0.

If 1/0=c, then 1=0*c=0. There is no choice of c that makes this true, so 1/0 cannot have a value. (Same problem shows up for any numerator except 0 itself.)

If 0/0=c, then 0=0*c. This is true for *all* choices of c, so there is no reason to choose any one of them over any other.

The short way of saying all this is: don't divide by zero.

*****

Some people are saying that 0/0 is "indeterminate". They aren't really talking about 0/0; they are talking about a ratio f(x)/g(x) where f(x) and g(x) both approach zero (this is calculus now). The deal is, even if you know that f(x) and g(x) both approach zero, that fact in itself gives you no information whatsoever about the ratio f(x)/g(x). Since the limit of that ratio cannot be determined, it is "indeterminate". The shorthand they use in calculus is that "0/0 is an indeterminate form", but they aren't really talking about the number 0 divided by the number 0.

2007-02-19 04:11:09 · answer #2 · answered by Doc B 6 · 1 0

It is literally undefined.

The DEFINITION of 1/x is that it is a number such that x * (1/x) = 1.

Since there is no y such that 0 * y = anything but 0, there is no 1/0.

And the DEFINITION of a/b is a * (1/b). Since there's no 1/0, there's also no a/0 for any other a, such as a=0.

2007-02-19 09:51:19 · answer #3 · answered by Curt Monash 7 · 1 0

0/0 Is NOT 0, infinite or 1. It is undefined. There is no exact answer. It doesn't exist. Unless you're talking about limits (Calculus) then it could equal Negative Infinity, or Infinity.
Any NON-ZERO number divided by itself is 1.
If the numerator in a fraction equals 0, then it is 0. If the denominator is 0, it's still undefined because you cannot divide by zero.

2007-02-19 05:06:57 · answer #4 · answered by Anonymous · 1 0

zero is a number but it itself has no value.
2/2=1,two is a numerical value,so when divided by itself the answer comes one
100/100=1,0 itself has no value
when it is used with a whole no. it acquires a value 100.
0/0=0,as 0 itself have no value so the answer anything other than 0 is unexpected.

2007-02-19 15:00:46 · answer #5 · answered by RIMPS 1 · 0 0

I think logic should apply here.

When you divide something, you are essentially breaking it into equal groups. 10/2 (10 divided by 2) means you have 10 units and you are seperating it into 2 equal groups. Yes, it gets a little more complicated when trying to divide by .5, but hopefully you can catch my drift.

How do you seperate something into 0 equal groups?

2007-02-19 04:19:02 · answer #6 · answered by Doug 5 · 0 0

Your demonstration gives you your answer: 0/0 is not defined. If it were defined then it would lead to precisely contradictions such as you have evidenced here. To avoid such contradictions it is not defined.

HTH

Charles

2007-02-19 04:06:45 · answer #7 · answered by Charles 6 · 1 0

0/0 is undefined.
because any number dividend by zero is undefined.the definition of rational number is a number written in the form of p/q where q is not equal to0.the formulae a/a is1 is applicable only if a is not equal to zero.

2007-02-21 22:32:39 · answer #8 · answered by Anonymous · 0 0

0/0 is indeterminate. If there are functions f(x) & g(x) both of which approach 0 in the limit that x--->the same value, you cab use L'Hospital's rule
lim x--->C f(x)/g(x)=limx--->C f'(x)/g'(x) if this is still indeterminate, go to f"(x)/g"(x) etc till you get a solution.

2007-02-19 05:06:59 · answer #9 · answered by yupchagee 7 · 0 0

there is no exact value - it is said as determinant form since 0/x is 0 and x/0 is infinity there is no value

2007-02-19 04:16:12 · answer #10 · answered by selva ganesh 3 · 0 0

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