i'm tryin 2 solve a theorem n i can't figure out the answer 2 this
2007-02-19 03:34:42 · 7 answers · asked by born2die 1 in Science & Mathematics ➔ Mathematics
(a^n-1 + b^n-1)(a^n-1 + b^n-1)
a^(2n-2) + 2a^(n-1)b^(n-1) + b^(2n-2)
ok thats all i got lol XD assuming you didnt mean a^n + 1 which is what u technically wrote lol
2007-02-19 03:40:32 · answer #1 · answered by Anonymous · 0⤊ 0⤋
( a^n - 1 + b^n -1 )
A = a^n-1 B = B^n-1 so
(A+B)^2 = A^2 + B^2 + 2 A B
= (a^n-1)^2 + (b^n-1)^2 + 2 (a^n-1) (b^n-1)
2007-02-19 03:40:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋
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2016-09-29 08:02:01 · answer #3 · answered by ? 4 · 0⤊ 0⤋
a ^ 7&3
2007-02-19 03:40:15 · answer #4 · answered by gismojabba 1 · 0⤊ 0⤋
a^2(n-1) + b^2(n-1) + 2(ab)^n-1
2007-02-19 03:38:39 · answer #5 · answered by gjmb1960 7 · 0⤊ 0⤋
=a^2n-2 +b^2n-2 + 2(ab)^n-1
2007-02-19 03:44:42 · answer #6 · answered by santmann2002 7 · 0⤊ 0⤋
a^(2n-2)+2a^(n-1)*b^(n-1)+b^(2n-2)
2007-02-19 03:41:42 · answer #7 · answered by Anonymous · 0⤊ 0⤋