I need to know if this problem can factor completely. If anyone knows that would be super. I need help. Thanks.
2007-02-19 02:37:29 · 7 answers · asked by Danielle 1 in Science & Mathematics ➔ Mathematics
Use the quadratic formula
a = -2
b = -8
c = -3
Solutions are:
[ -b ± sqrt(b² - (4)(a)(c)) ] / 2a
The quadratic you have listed will not factor cleanly without this.
2007-02-19 02:47:40 · answer #1 · answered by MamaMia © 7 · 0⤊ 0⤋
It is prime and can't be factored. To check if a quadratic
(ax^2 + bx + c)can be factored, look at b^2 - 4ac. That's the discriminant, if it is a perfect square like 0,1,4 9,16... then the quadratic is factorable. If it's not (in this case, it's = 40) then it is not factorable or prime.
2007-02-19 02:57:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
-(2x^2 + 8x + 3)
It is not factorable into whole numbers
(2x +3)(x + 1) or (2x + 1)(x + 3) are the only choices.
Neither gives you 8x in the middle.
2007-02-19 02:45:34 · answer #3 · answered by richardwptljc 6 · 0⤊ 1⤋
2 (x + 2 + (â10)/2) (x + 2 - (â10)/2 )
2007-02-19 02:49:51 · answer #4 · answered by â?¥ cheeze â?¥ 2 · 0⤊ 0⤋
let a=-2
b=-8
c=-3
use the formula -b+- square root of b squared -4ac all over 2a or the quadratic formula
the answer is 8-square root of 75 all over 4 and 8+square root of 75 all over 4
gets?
2007-02-23 00:26:23 · answer #5 · answered by joy14 1 · 0⤊ 0⤋
this problem is not factorable.
to find x just use the quadratic formula.
2007-02-19 02:54:56 · answer #6 · answered by PROUD TO BE A LIBERAL TEEN! 4 · 0⤊ 0⤋
mmmm... and how
2007-02-19 04:37:15 · answer #7 · answered by KASTA 2 · 0⤊ 0⤋