A brown eyed man is married to blue eyed women. They have one child with blue eyes?

Question

A brown eyed man is married to blue eyed women. They have one child with blue eyes. What is the
(A) genotype of man
(B) genotype of woman
(C) genotyp of blue eyed child
(D) gamete probability of man
(E) probobility of next child having brown eyes

Answer 1

If B represents the allele for Brown eyes and b for blue eyes:

(A) The genotype of man would be Bb
(B) The genotype of woman would be bb
(C) The genotype of blue eyed child would also be bb
(D) The man would have B and b gametes at a 1:1 ratio
(E) The probability of next child having brown eyes would be 50%

Answer 2

For the following answers, E=brown eyes and e=blue eyes. When it comes to genes, there are usually different variations of the genes; in the variations, there is usually a heirachial system, meaning that some variations of the gene with be more dominant than others and that gene will show itself. In eyes, brown coloration is dominant to blue coloration, and children (called gametes) inherit a gene from each parent. This means that if a gametes genotype (it's genes, one from each parent) is EE or Ee, it will have brown eyes; however, if it has a genotype of ee, then it will have blue eyes. Here is a chart (called a Punnett Square) showing the chances of inheritance.

___|___E___|___e___|
_E_|___EE__|__Ee___|
_e_|___Ee___|__ee___|


Each square is one of four, so each square = 25% probability of that being the offspring genotype. (The Es and es on the side and top are the genotypes of hypothetical parents, just as an example; it's not the answer to this question.) There is one square for EE (25%), two square for Ee (50%), and one square for ee (25%); because brown eyes can be expressed by either EE or Ee, there is a 75% chance of brown eyes and a 25 percent chance of blue eyes.
However, gametes with the Ee genotype still have a chance of passing their e gene to their gametes even though they have brown eyes. This is the genotype of the father. Because the mother has blue eyes, then her genotype must be ee. Therefore, their Punnett square looks like this:

___|___e___|___e___|
_E_|___Ee__|__Ee___|
_e_|___ee___|__ee___|

Since the child has blue eyes, it's genotype must be ee, and there is a fifty fifty chance of the next child having either blue or brown eyes.

(A) Ee
(B) ee
(C) ee
(D) Unfortunately, I can't answer this question. I would need to know which gamete of the man to find the probability of.
(E) 50%

Answer 3

There is a good chance the man is homozygous; if he wasn't, each kid would have had a 50% of being blue eyed, and to have 10 child with brown eyes in that condition has a probability of about 1 in 1000. If the 11 th child has also brown eyes, it is still not a proof. There is still a 0.0488% (1 in 2048) probability that this could happen with a heterozygous father. If the 11th child has blue eyes, then this is proof that the father is not homozygous.

Answer 4

Brown eyes are dominant over blue. Let B=brown eyes/ b=blue eyes.
A) The genotype of the man MUST be B/b, because that is the only way his child could get one gene for blue eyes with the man having brown.
B) The woman must be b/b because blue is completely recessive to brown.
C) Hence, the kid must also be b/b
D) 50%B, 50%b
E) 50% (do the punnet square...any homozygous B's or heterozygotes will have brown eyes.)
Hope that helps!

Answer 5

genotype of man is blue x brown (heterozygota)
genotype of woman is blue xblue (homozygota)
genotype of child is blue x blue (homozygota)
probability of next child having brown eyes 50%
gamete probability of man? 50% if it's what I think it is.

Answer 6

Man that allmost sounds like my family. I am the only one with brown eyes out of all seven of us kids. The man has to be Bb and the woman is bb-- the only way to have blue eyes is to have a bb since B is the dominant trait. There is a greater chance that any other children that these two would have would also have blue eyes instead of brown.

Answer 7

A. Bb
B. bb
C. bb
D. (don't understand this one because you can't get the chance of the male or female from this question)
E. 50% (because for a brown eyed man and a blue eyed woman to have any blue eyed children. The brown eyed man has to have a recessive blue trait.)

Answer 8

Brown eyes are dominate trait, and blue eyes recessive.
The man would have to have a recessive blue eye trait..
B=brown b=blue
man is Bb, women is bb
... b....b
B Bb Bb
b bb bb
(ignore the dots above.. only way to make the chart)
so they have a 50% probability of having a child with blue eyes, and 50% prob. of having a child with brown eyes.
The child with blue eyes is bb.

Answer 9

Ewwwwww.
This is based on the old (and wrong) belief that eye color is caused by a simple dominance pattern (it is not, it involves multiple allelles.)

The way to do this is with a punnet square.
If you don't know how, look here:
http://www.usoe.k12.ut.us/CURR/Science/sciber00/7th/genetics/sciber/punnett.htm

and here:
http://en.wikipedia.org/wiki/Punnett_square

Here is a virtual punnet square builder:
http://www.athro.com/evo/gen/punexam.html

For the purposes of this question, it looks like blue is bb. (Brown would be BB or Bb)

Take the time to learn how to do a punnet square for yourself- they are wicked easy points on your next test.

Answer 10

well it comes from genetics of course....
but thats just how my family is! my dad has brown eyes and my mom has blue eyes and they had me as their first child and i have blue eyes! and my sister Kelly has brown eyes! yeah...
i dont know what genotyp is....genetics? okay nvermnd.