2007-02-19 01:52:20 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
No
2007-02-19 01:55:26 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Yes, any quadratic like this can be factored.
2x^2 - 3x +2 = 2 (x - R1) (x - R2)
where
R1 = ( 3 + sqrt(-7) ) /4
R2 = ( 3 - sqrt(-7) ) / 4
sqrt = square root
If you don't understand how to get the square root of a negative number, then you'll have to ask your math teacher.
2007-02-19 10:07:38 · answer #2 · answered by morningfoxnorth 6 · 0⤊ 0⤋
No.
since Delta=3^2 -4*2*2= -7<0
it can't be factored
2007-02-19 10:08:20 · answer #3 · answered by whimgurl 1 · 0⤊ 0⤋
The discriminant b²-4ac = -7, so the quadratic has no real roots and can't be factored (not with real coefficients anyway).
2007-02-19 10:00:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
No
(x - 2)(x - 1) = x² - 3x + 2
The equation is 2x² - 3x + 2
Totally two different equations
- - - - - - - - - - - - - -s-
2007-02-19 10:04:32 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
Yes.
(x-2) (x-1)
2007-02-19 09:57:36 · answer #6 · answered by Mr. Wonderful 1 · 0⤊ 2⤋
look! is there any intersection with x axis? if no so it can not be factored
2007-02-19 12:42:59 · answer #7 · answered by KASTA 2 · 0⤊ 0⤋
um NO this sum CAN NOT be factored.I think
2007-02-19 10:55:14 · answer #8 · answered by Amal 2 · 0⤊ 0⤋
no it can't be factored
2007-02-19 10:01:18 · answer #9 · answered by sarah 3 · 0⤊ 2⤋
(4x-3-|/7i)(4x-e+|/7i)
:)
anything quadratic can be factored!
2007-02-19 09:58:59 · answer #10 · answered by mikedotcom 5 · 0⤊ 0⤋