convert these integers from decimal notation to binary notation?

Question

A. 231
b. 4532
c. 97644

with solution pls

Answer 1

I'll show you how to do the first one, but you'll have to do the other two yourself.

Divide 231 by 2. Result = 115, remainder = 1. Write down 1.

Divide 115 by 2. Result = 57, remainder = 1. Write down 1 to the left of the first 1 you have written.

Divide 57 by 2. Result = 28, remainder = 1. Write down 1 to the left of the other digits.

Divide 28 by 2. Result = 14, remainder = 0. Write down 0 to the left of the other digits.

Divide 14 by 2. Result = 7, remainder = 0. Write down 0 to the left of the other digits.

Divide 7 by 2. Result = 3, remainder = 1. Write down 1 to the left of the other digits.

Divide 3 by 2. Result = 1, remainder = 1. Write down 1 to the left of the other digits.

Divide 1 by 2. Result = 0, remainder = 1. Write down 1 to the left of the other digits.

Stop.

The string of digits which you have written is the answer.

Answer 2

Keep dividing 2 into 231 and the subsequent integral
answers and keep track of the carry over numbers.

231 / 2 = 115 + carry of 1
115 / 2 = 57 + carry of 1
57 / 2 = 28 + carry of 1
28 / 2 = 14 + carry of 0
14 / 2 = 7 + carry of 0
7 / 2 = 3 + carry of 1
3 / 2 = 1 + carry of 1
1 / 2 = 0 + carry of 1

Now, reading backwards (from the bottom), the carry numbers
are 111000111, which is decimal 231 in binary notation.

Check yourself that the others are :

4532 = 1000110110100

97644 = 10111110101101100

Answer 3

231 = 128 + 64 + 32 + 4 + 2 + 1
= 1*(2^7) + 1*(2^6) + 1*(2^5) + 0*(2^4) + 0*(2^3) + 1*(2^2)
+ 1*(2^1) + 1*(2^0)

So 231 ( in base 10) equals 11100111 in base 2

Now you can do the others; write them as sums of powers of 2 and determine the coefficients (the zeros and ones)

Answer 4

There are 10 kinds of people in the world:

Those that understand binary
and those that don't.

Answer 5

Check this link;

http://www.pc-control.co.uk/binary_number_system.htm

231 = 11100111

You should be able to do the rest.