Show that when the depth of water is h cm, the volume of water, V, is given by V= (25pi/192)h^3
Please show your working and steps clearly thanks!
2007-02-18 19:26:38 · 4 answers · asked by saffy 2 in Science & Mathematics ➔ Mathematics
If the cone has the vertex at the bottom, opening upwards, r/h = 10/16 by similar triangles.
V = (1/3)πr²h
r = 10h/16
V = (1/3)π(10h/16)²h
V = (1/3)π(5h/8)²h
V = (1/3)π(25h²/64)h
V = (25π/192)h³
2007-02-18 20:07:47 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
volume of cone is Base x good /3 so which you have your: h= 15 r= 4 Bh/3 15x (3.14)(4) -------------------- 3 = sixty 2.8 gadgets of water yet via actuality it in person-friendly words holds as much as 10cm and its finished is 15cm, you come across the version... So 5cm. Bh/3 5x (3.14)(4) ----------------- 3 = 20.ninety 3 untils of water Subtract sixty 2.8- 20.ninety 3 = 40-one.87 untils of water. Im not sure if that's what the respond says. Or, do you understand calculus to do it...
2016-12-17 13:32:24 · answer #2 · answered by ? 4 · 0⤊ 0⤋
volume(v) = (1/3)base(b) x height(h)
v = (1/3)pi(r^2)h
= (1/3)pi(r^2/h^2)h^3
= (1/3)pi(10^2/16^2)h^3
= (25pi/192)h^3
--------
Reason:
r/h = 10/16 at any water level.
2007-02-18 19:37:29 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
Look. I don't do my own homework why would I do yours. Multiply 16cm and 10cm.
2007-02-18 19:36:10 · answer #4 · answered by darrkadlubowski 3 · 0⤊ 1⤋