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or what other scenarios cause non covergence? any help is appreciated.

2007-02-18 18:11:39 · 2 answers · asked by doverbeach 3 in Science & Mathematics Mathematics

2 answers

♠ when you solve an equation F(x)=0 you have to transform it like this:
x=f(x) to use Newton’s method;
♣ if |f’(x)| < 1 in vicinity of supposed root x, the method works and procedure converges;
if |f’(x)| > 1, the procedure diverges;
if some |f’(x)| > 1 while others < 1 the procedure cycles;
♦ example: x^2 = 27, find x; Newton’s method: x=0.5*(27/x +x) =f(x);
f’(x) = 0.5*(-27/x^2 +1); suppose x=5, then f’(5) = 0.5*(-27/25 +1) < 1; thus method is expected to work;
♥ example: x=sqrt(tan(x-0.5)) diverges; try another combination
x=f(x), i.e. x=atan(x^2)+0.5, it converges;

2007-02-19 03:06:14 · answer #1 · answered by Anonymous · 0 0

you should draw the graph of the function you are examining to see what could happen

cycling is one
also it can simply diverge

2007-02-19 02:35:16 · answer #2 · answered by gjmb1960 7 · 0 0

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