Magnitude of the gravitational force b/t the earth and the moon?

Question

What is the magnitude of the gravitational force between the earth (5.98x10^25kg) and the moon (7.35x10^22kg)?

Answer 1

[G x M moon x M earth] / distance^2

(6.67 x 10^-11)(5.98 x 10^24)(7.35 x 10^22) / (384,400)^2

Answer 2

Well, first off, remeber that the force from the moon to the earth decreases during low tide and increases during high tide.
Issac Newton's formula formula to find this sort of thing out is:
F = G * m1 * m2 / r^2
G is the gravitational constant, m1 and m2 are the masses of each body, and r is the distance between them.

F=G *(5.98X10^25kg)*(7.35X10^22kg)/ distanceXdistance
F=G*(5.98X10^25kg)*(7.35X10^22kg)/ (238,854 X 238,854)
F=G*(5.98X10^25kg)*(7.35X10^22kg)/ 570,512,033
F=G*(59.8X59.8)
F=G*(3576.04)
F=3576.04G
F-3567.04 X (6.67 x 10-11 N m2/kg2)
F=3657.04 X (6.67 X 10)
F=3657.04 X 66.7
F=243924.568 kilograms/mile
(OR)
F=537,760.98 pounds/mile

Answer 3

The moon is about 250,000 miles from the Earth
The surface of the Earth is about 4000 miles from the center of the Earth.
The acceleration at the surface of the earth should be 250*250/4/4 =1,000,000
times the acceleration that the moon experiences.
Force = M*A
7.35*10^22*9.8/1000000=7.2*10^17 Newtons

Answer 4

you need to use F=G*m1*m2/r*r defined by ability of newton yet be cautious it incredibly is barely valid for element hundreds. in case you're calculating the gravitational between earth and moon you're able to evaluate the 2d of inertia and then attempt to calculate the gravitational stress.

Answer 5

A = L/2m2 T = p a b ==> T = 2m2pa b/L