(7x)(8x) just 56? what do I do with the x?
2007-02-18 11:01:04 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
(7x)(8x)=56to the second power.
think of it as
7x(to the first power) x 8x(to the first power)=
Multiply the #s and add the exponents.
=56+x(to the first power)+x(to the first power)
56xsquared(to the second power)
2007-02-18 11:12:53 · answer #1 · answered by robinbird 2 · 0⤊ 0⤋
You have the 56 part right. Then you have to square the X. So you would end up with 56X^2. You square the X b/c X can be any number.
It is the same as multiplying 2 by 2, which is 4 (or 2 squared).
2007-02-18 19:28:40 · answer #2 · answered by FLipping Tonks 2 · 0⤊ 0⤋
The person above is correct in telling you that (7x)(8x)=56x^2.
You multiply 7*8 then multiply x*x so you have 56 and two x's or x^2.
However, if you were to add these numbers i.e. 7x+8x, it would be 15x, not 56x.
2007-02-18 19:10:47 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Square it.
(7x)(8x)=56x^2
whereas 7x + 8x = 15x
Sorry, got ahead of myself. In the other example it's 15 not 56, she's right. I fixed it. :)
2007-02-18 19:06:06 · answer #4 · answered by Ciano 3 · 0⤊ 1⤋
That's not right...it has to be 56x^2. Wherever that answer is, even if it's in a textbook, it's wrong.
2007-02-18 19:08:38 · answer #5 · answered by booda2009 5 · 0⤊ 1⤋
56x(squared)
2007-02-18 19:09:00 · answer #6 · answered by shelbin 2 · 0⤊ 1⤋