Help with last binding energy!!physics!`?

Question

calculate the binding energy of the last neutron in the calcium mass number 43 & atomic number 20 nucleus. ( hint u shoul d compare the mass of calcium atomice number 20 & mass # 42 plus the mass of a neutron,


PLz show me how to do it. Promise to give u 10 points if u help me with the question, THNX

Answer 1

p n atomic mass
42Ca 20 22 41.9586180
43Ca 20 23 42.9587666
The binding energy =Mc^2 where the M is the difference in mass between ca(42)+n and ca(43)