Electricity can be a hazard in hospitals, particularly to patients who are connected to electrodes, such as an ECG. For example, suppose that the motor of a motorized bed shorts out to the bed frame, and the bed frame's connection to a ground has broken (or was not there in the first place). If a nurse touches the bed and the patient at the same time, she becomes a conductor and a complete circuit can be made through the patient to ground through the ECG apparatus. (where V = 220 V and R (the nurse) = 1.00E4 . Calculate the current through the patient.
2007-02-18 08:10:18 · 5 answers · asked by webogirl 2 in Science & Mathematics ➔ Physics
Answer needs to be in mA. Thanks!
2007-02-18 08:17:36 · update #1
Actually, the answer turned out to be 7.3mA.
220/(1.0E4 +1.0E4 +1.0E4)
There are three resistors...
2007-02-21 13:58:34 · update #2
22mA, but it would take 100mA directly through the heart to induce fibulation.
2007-02-22 00:59:39 · answer #1 · answered by joshnya68 4 · 0⤊ 0⤋
Does R = 10 ^(4) ⦠?
If so :-
I = V / R = 220 / 10^(4) A = 220 x 10³ / 10^(4) mA
I = 22 mA
2007-02-18 08:59:03 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Use the formula V=IR
that is 220=1.00e4 x Resistance
Resistance = 220/1.00E4
2007-02-18 08:13:47 · answer #3 · answered by mary l 1 · 0⤊ 2⤋
Ohm's Law
V=Ri = resistance x current
current = (220V) / (10^4) = 22mA
2007-02-18 08:19:55 · answer #4 · answered by Ghidorah 3 · 1⤊ 1⤋
A simple Ohm's Law problem........
I = E / R
220V / 1.00E4 = 0.022 Amps = 22mA
2007-02-18 08:18:57 · answer #5 · answered by Diogenes 7 · 1⤊ 0⤋