2007-02-18 07:52:08 · 8 answers · asked by spanishfly_100 1 in Science & Mathematics ➔ Mathematics
I think you meant:
(x^2+5x-4)(x^2-x+2)
Since it is just multiplication, start by breaking down the problem:
x^2(x^2-x+2)
5x(x^2-x+2)
-4(x^2-x+2)
Now, distribute each of the terms you have factored:
x^2(x^2-x+2) = x^4 - x^3 + 2x^2
5x(x^2-x+2) = 5x^3 - 5x^2 + 10x
-4(x^2-x+2) = -4x^2 + 4x -8
Take the answers from the factored terms and simplify them.
x^4 - x^3 + 2x^2
____5x^3 - 5x^2 + 10x
_________-4x^2 + 4x - 8
.............................................
x^4 + 4x^3 - 7x^2+ 14x -8
Your answer is:
x^4 + 4x^3 - 7x^2+ 14x -8
2007-02-18 08:18:35 · answer #1 · answered by Sparkles 3 · 1⤊ 0⤋
1 over 4x(squared) 2/5 power of 5
2016-05-24 03:30:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Simplify (x^2+5x-4)(x^2-x+2)
First: eliminate parenthesis by using the Foiling Method.
(x^2)(x^2)+(x^2)(-x)+(x^2)(2)+(5x)(x^2)+(5x)(-x)+(5x)(2)+(4)(x^2)+(4)(-x)+(4)(2)
Sec: combine the terms.
(x^4)+(-x^3)+(2x^2)+(5x^3)+(-5x^2)+(10x)+(4x^2)+(-4x)+(8)
x^4 - x^3 + 2x^2 + 5x^3 - 5x^2 + 10x + 4x^2 - 4x + 8
Third: combine "like" terms.
x^4 - x^3 + 5x^3 + 2x^2 - 5x^2 + 4x^2 + 10x - 4x + 8
x^4 + 4x^3 + x^2 + 14x + 8
2007-02-18 09:27:32 · answer #3 · answered by ♪♥Annie♥♪ 6 · 0⤊ 2⤋
x^4-x^3+2x^2+5x^3-5x^2+10x-4x^2-4x-8
Now simplify
2007-02-18 08:05:24 · answer #4 · answered by blabberhog12 1 · 1⤊ 0⤋
(x2+5x-4)(x2-x+2)
=(7x-4)(x2-x+2)
=(3x)(2-x+2)
=(3x)(4x)
=12x
I think it's 12x but I'm not sure
2007-02-18 08:03:56 · answer #5 · answered by squ_ishy07 3 · 1⤊ 2⤋
x^4+4x^3-7x^3+14x-8
2007-02-18 09:07:42 · answer #6 · answered by Anonymous · 1⤊ 2⤋
No, I don't feel like it!!!
2007-02-18 07:59:32 · answer #7 · answered by Anonymous · 1⤊ 2⤋
All matematical Equation have only one solution
= 0
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2007-02-18 08:03:34 · answer #8 · answered by Praveen 2 · 1⤊ 2⤋