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find the remaining trigonometric ratios if sin=.23 HOW DO YOU DO IT ON A CALCULATOR??
thank you!!

2007-02-18 07:50:16 · 4 answers · asked by mandy 2 in Science & Mathematics Mathematics

4 answers

You could use the sin^(-1) function on a calculator to find out the angle, then find the cos, tan, etc. of that angle. Or, if you don't want to use inverse functions (or don't have them on your calculator), all you need to do is figure out what cos is and you can get all the other functions.

There's a trig identity:
sin(x)^2 + cos(x)^2 = 1.
Let's say x = the angle
So 1 - (0.23)^2 = cos(x)^2
So cos(x) = sqrt(1 - (0.23)^2), which is approximately .9732

Then tan(x) is sin(x)/cos(x)
tan(x) = .23/.9732, which is approximately .2363
csc(x) is 1/sin(x), so it's 1/.23, which is approximately 4.348
sec(x) is 1/cos(x), so it's 1/.9732, which is approximately 1.028
cot(x) is cos(x)/sin(x), which is approximately 4.231

2007-02-18 08:01:41 · answer #1 · answered by Anonymous · 2 0

use sin^(-1) function to get the angle

then use the that angle to find the rest

2007-02-18 07:53:26 · answer #2 · answered by Flaming Pope 4 · 0 0

I think this is what you mean:
sin^2+cos^2=1
sin^2=-cos^2 +1
.004^2=.000016-1+1
.000016=-cos^2+0
-cos^2=1-000016
(-cos^2=cos^2)
1-.000016=.999984
cos^2=.999984
cos=.999984

I think this is is right and hope it helps.

2007-02-18 08:18:10 · answer #3 · answered by Matthew P 4 · 0 1

arc sine.

2007-02-18 07:53:57 · answer #4 · answered by Anonymous · 0 0

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