math question?

Question

A servant had $100 to buy 100 animals. A cow was $5, a goat $1,and chickens 5 cents each.How many of each animal could the servant buy if he buys at least one of each animal?

Answer 1

Is this an inequality/equality question?

In any case, this is how I would set it up...
a=# of cows
b=# of goats
c=# of chickens

100≥5a + b + .05c, and
100=5a + b + .05c

so, $100 is greater than or equal to 5a + b + .05c.

I think you could solve this by substitution.

Unless someone has a better suggestion? Depends which unit you're working on and how they want you to solve it.

Answer 2

Call a ,b and c the number of cows,goats and chicken

5a+b+0.05c=100
a+b+c=100
From the first as a and b must be integers 0.05c must be an integer
So0.05c=k and c=20 k (k=1,2,3 or 4) because if you take k = 5
the number of chicken would be 100.You must try with those four cases but if k=4 c=80

5a+b=96
a+b=20 so 4a = 76 and a =19 b= 1 c=80

You´ll buy 19cows 1goat and 80 chicken