equation math question?

Question

i need help to solve this equation, i have no idea (maths not my strongest subject,can someone help please

x^2 + 7x + 2 = 0

Answer 1

First: you need to use the Quadtracti Equation which is,

x = [- b +/- V`b^2 - 4ac] / 2a

Sec: there are three terms for three variables.

a = 1
b = 7
c = 2

*Replace the terms with the corresponding variables.

x = [- 7 +/- V`7^2 - 4(1)(2)] / 2(1)

x = [- 7 +/- V`7^2 - 4(1)(2)] / 2

x = [- 7 +/- V`7*7 - 4(1)(2)] / 2

x = [- 7 +/- V`49 - 4(1)(2)] / 2

x = [- 7 +/- V`49 - 4(2)] / 2

x = [- 7 +/- V`49 - 8] / 2

x = [- 7 +/- V`41] / 2

Third: you have two solutions.

1. x = [- 7 + V`41] / 2
x = - 7/2 + (V`41)/2

2. x = [- 7 - V`41] / 2
x = - 7/2 - (V`41)/2

Solutions: -7/2 + (V`41)/2 and -7/2 - (V`41)/2

Answer 2

Use the quadratic formula. The general form is ax^2 + bx + c = 0 and in this problem a=1, b=7 and c=2.

Answer 3

It's not factorable, so you have to use the quadratic formula:
x=-b±√b^2-4ac/2a
a=1,b=7,c=2
x=(-7±√(7)^2-4(1*2))/2(1)
x=(-7±√49-4(2))/2
x=(-7±√49-8)/2
x=-7±√41/2
x=-.298 or -6.702

I hope this helps and good luck with your math class!

Answer 4

x² + 7x + 2

a = 1

b = 7

c = 2

Quadratic formula

x = - b ± √b² - 4ac / 2a

x = - 7 ± √(7)² - 4(1)(2) / 2(1)

X = - 7± √49 - 8/ 2

x = - 7 ± √41 / 2

x = - 7 ± 6.403124237 / 2

- - - - - - - - - - -

Solving for +

X = - 7 + 6.403124237 / 2

x = - 0.596875763 / 2

x = 0.298437881

- - - - - - - -

Solving for -

X = - 7 - 6.403124237 / 2

x = - 13.40312424 / 2

x = - 6.701562119

- - - - - - - - - - - - -s-

Answer 5

Everybody here says "use the quadratic equation" and that's good but it's not the only way. Whatever happened to completing the square?

x²+7x+2=0
so 7/2=3.5
and 3.5²=12.25
so we need to add 10.25 to both sides to get
x²+7x+12.25=10.25
this can be rewritten as:
(x+3.5)²=10.25
now take the square root of both sides
x+3.5=±3.2016
subtract 3.5 from both sides
x=-3.5±3.2016
x=-6.7016 , -.2984

Answer 6

Solve by using the quadratic formula:

a = 1
b = 7
c = 2

x = (-b +- sqrt(b^2 - 4ac))/(2a)

= (-7 +- sqrt(7^2 - 4(1)(2))/(2(1))

= (-7 +- sqrt(41))/2 <------exact answer

= -.2984, -6.7016 <---------approx. answer

Answer 7

This can't be factored so used the quadratic....

a=1
b =7
c=2

Answer 8

You need to use the quadratic formula
x = -b +- sqrt(b^2-4ac)
-------------------------
2a

a is coefficent of x^2, b of x, and c is the number

x= -7+- sqrt(7^2-4(1)(2))
--------------------------
2

x = -6.70 and x = -0.298

Answer 9

use quadradic fomula

-b +/- sqr(b^2 - 4ac)
------------------------
........ 2a

standard form is Ax^2 + Bx +C = 0
1 is A
7 is B
2 is C

-7 +/- sqr ( (-7)^2 - 4(1)(2)
----------------------------------
................ 2(1)

that reduces to:
-7 +/- sqr (41)
-----------------
...... 2

hope this helps.

Answer 10

X=No solution