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heya I need some help with random qs,

y=ln(4x-2) dy/dx=?

y=(cos²x)/lnx dy/dx=?

and what does finding the derivatives of cotx mean?

any help appretiated

2007-02-18 04:55:07 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

y=ln(4x-2) dy/dx=?
y'=4/(4x-2)

y=(cos²x)/lnx dy/dx=?
y'= -2sinxcosx lnx- (1/x)(cos^ ² x)

=-sin2x-(1/x)(cos^ ² x)



y=cotx=cosx/sinx
y'=( - sin^2 x-cos^2 x) /cos^2 x

= - 1/cos^2 x

2007-02-18 05:10:27 · answer #1 · answered by iyiogrenci 6 · 0 0

I honestly don't know. if i hadn't just woken up 5 minutes ago, i would be able to help, but i'm too tired to think!

2007-02-18 12:59:19 · answer #2 · answered by Isabella 1 · 0 0

i donno i already had math class today!

2007-02-18 12:57:29 · answer #3 · answered by Sarah72 2 · 0 0

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