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2007-02-18 04:40:34 · 38 answers · asked by CHELSEA R 1 in Science & Mathematics Mathematics

38 answers

5 = 3125

Multiply the previous number by 5 each time.

2007-02-18 04:45:35 · answer #1 · answered by roxpox99 3 · 1 1

These are the various powers of 5.

5 to the power of 1 = 5
5 to the power of 2 = 5 x 5 = 25
5 to the power of 3 = 5 x 5 x 5 = 125

So therefore 5 = 3125
and 6 = 15 625

2007-02-18 06:48:13 · answer #2 · answered by Anonymous · 1 1

3125.
this is the fifth term in a GP with a common ratio of 5.

thus 5= 5^5=625*5=3125

2007-02-18 04:45:48 · answer #3 · answered by s_d_sondhi 2 · 1 1

So it's 5^1, 5^2, 5^3, 5^4 and 5^5 =3125

2007-02-18 04:44:46 · answer #4 · answered by lynn y 3 · 1 1

The initial number in each case is the power to which 5 is raised to give the final number (e.g. 3=125 because 5^3=125). Therefore the number 5 would give you 5^5, i.e. 5x5x5x5x5, which is 3125.

2007-02-19 06:43:30 · answer #5 · answered by general_ego 3 · 0 1

1= 5, 2= 25, 3= 125, 4 = 626 5 = 3125

The answer is 5 = 3125

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2007-02-18 04:49:10 · answer #6 · answered by SAMUEL D 7 · 1 1

3125. the first numbers are the powers to which the number 5 is raised. For example 5 to the power 2 (or 5 squared) is 5 times itself twice that is 5x5=25.

2007-02-18 04:50:40 · answer #7 · answered by R.E.M.E. 5 · 1 1

u can work it out with this simply using powers
5 to the power 1 = 5
5 to the power 2 = 25
5 to the power 3 = 125
5 to the power 4 = 625
5 to the power 5 = 3125

2007-02-18 05:25:15 · answer #8 · answered by Maths Dummy 1 · 1 1

Whatever 625 x 5 is girl

2007-02-19 01:17:36 · answer #9 · answered by Sluugy 5 · 0 1

It's not correct to say 1=5, 2=25 ect. (impossible)
If you mean 1st term=5^1=5
2nd term=5^2=25
3rd term=5^3=125
4th term=5^4=625
then 5th term=5^5=3125

2007-02-18 05:43:05 · answer #10 · answered by hirunisha 2 · 0 1

5= 3125

2007-02-18 04:43:37 · answer #11 · answered by Anonymous · 1 1

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