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4 answers

For the X-OR gate you would need 4 NAND gates, after that you should use one more NAND gate to obtain the X-NOR gate the two inputs of the NAND gate should be connected together and the NAND gate should be then placed at the output of the XOR gate. so the answer is 5 NAND gates are needed at least to make an X-NOR gate. i wish i could attach a diagram pic to this but it's impossible:(. i guess you should just imgine the thing. when u make the inputs of the NAND similar it works just like a NOT gate.

2007-02-18 05:34:53 · answer #1 · answered by R1 1 · 0 0

You have to use atleast 5 nand gates to build a x-nor gate.
x-nor=AB+(AB)'
nand gate=(AB)'
using 1 nand gate we can get (AB)'
again 2 nand gates are used to find out A' and B'
taking A' and B' as input we have take another nand gate toget (A'B')'as output.
again we have totake another nand gate where inputs are (AB)' and
(A'B')'
hence using 5 nand gates we can get the out put which is equal to x-nor gate.

2007-02-18 12:52:11 · answer #2 · answered by rojalin 104 1 · 0 0

Hi. 4 http://www.answers.com/topic/nor-gate for a NOR, 5 http://en.wikipedia.org/wiki/XNOR_gate for exclusive NOR.

2007-02-18 12:48:19 · answer #3 · answered by Cirric 7 · 0 0

This is no different to working with the logical operators. Wikipedia strikes again .. ;o)


HTH

2007-02-18 12:49:33 · answer #4 · answered by Chipz 3 · 0 0

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