Solve the system {2/5x+3/5y=2 7/3x-5/4y=-5}?

Question

Solve The System:
{2/5x+3/5y=2
{7/3x-5/4y=-5

Answer 1

to solve using elimination:

2/5x+3/5y=2
7/3x-5/4y=-5

multiply the top by 5 to get rid of the fractions there and the bottom by 12 to get rid of the fractions there.

2x+3y=10
28x-15y=-60

multiply the top by 5, add an eliminate the y's

10x+15y=50
28x-15y=-60

38x=-10
x= -10/38 x= -5/19

use either of the equations, substitute in x and solve for y

2x+3y=10
2(-5/19) + 3y = 10
y = [10 + 2(5/19)]/3
y = [(190/19) + (10/19)]/3
y = (200/19)/3
y = 200/57

x= -5/19 y = 200/57

check by substituting these values into the original equations

Answer 2

A) no solution (NONE OF THE ANSWERS ARE CORRECT (-2, -5) 1) y=x2+3x+5 y=5x+5 2) (5x+5)=-5 5x= -10 x=-2 So, you plug in x (-2) to find the value of y y= (-2)2+3(-2)+5 y=-4-6+5 y= -5 The answer is x= -2, y= -5, aka (-2,-5) option A.) would not be correct, because there is a solution and you can find it. The correct answer should be (-2,-5) or NONE OF THE ABOVE, all answers are wrong!

Answer 3

solve one equation for a variable and plug it into the other
x+Y =10
x=10-y
28(10-y)-15= -60
280-28y-15=-60
y=11.67
x=-1.67

i used a lot of common denominators